Concept explainers
(a)
Interpretation :
The amount of FeCO3 and K2SO4 in mg must be calculated which will be obtained from 10 mg of FeSO4. The mole ratio used for the conversion must also be clearly indicated.
Concept Introduction :
1 mol FeSO4 (molar mass 152 g) produces 1 mol FeCO3 (molar mass 116 g) and 1 mol K2SO4 (molar mass 174 g).
(a)
Answer to Problem 16A
Amount of FeCO3 and K2SO4 in mg will be 7.63 mg and 11.45 mg respectively. Moles ratio used for both the cases is (1:1).
Explanation of Solution
The
As per the balanced chemical equation,
152 mg FeSO4 produces 116 mg FeCO3.
1 mg FeSO4 produces
10 mg FeSO4 produces
Here,
152 mg FeSO4 produces 174 mg K2SO4.
1 mg FeSO4 produces
10 mg FeSO4 produces
b)
Interpretation :
The amount of CrCl3 and Sn in mg must be calculated which will be obtained from 10 mg of Cr. The mole ratio used for the conversion must also be clearly indicated.
Concept Introduction :
4 mol CrCl3 (molar mass 158 g) produces 4 mol Cr (molar mass 52 g) and 3 mol Sn (molar mass 119 g).
b)
Answer to Problem 16A
Amount of CrCl3 and Sn in mg will be 30.38 mg and 17.16 mg respectively. Mole ratio used for Cr to CrCl3 is (1:1) and for Cr to Sn is (4:3).
Explanation of Solution
The reaction is represented as follows:
As per the balanced chemical equation,
52 mg Cr produces 158 mg CrCl3.
1 mg Cr produces
10 mg Cr produces
Also,
1 mg Cr produces
10 mg Cr produces
c)
Interpretation :
The amount of Fe2S3 in mg must be calculated which will be obtained from 10 mg of S8. The mole ratio used for the conversion must also be clearly indicated.
Concept Introduction :
3 mol S8 (molar mass 256 g) produces 8 moles Fe2S3 (molar mass 208 g).
c)
Answer to Problem 16A
Amount of Fe2S3 in mg will be 21.67 mg. Mole ratio used for S8 to Fe2S3 is (3:8).
Explanation of Solution
The balanced chemical reaction is as follows:
As per the balanced chemical equation,
1 mg S8 produces
10 mg S8 produces
d)
Interpretation :
The amount of AgNO3, H2O and NO in mg must be calculated which will be obtained from 10 mg of HNO3. The mole ratio used for the conversion must also be clearly indicated.
Concept Introduction :
4 moles of HNO3 (molar mass 63 g) produces 3 moles AgNO3 (molar mass 170 g), 2 moles of H2O (molar mass 18 g) and one mole of NO (molar mass 30 g).
d)
Answer to Problem 16A
Amount of AgNO3, H2O and NO in mg will be 202.38 mg, 1.43 mg and 1.19 mg respectively. Mole ratio used for HNO3 to AgNO3, H2O and NO are (4:3), (4:1) and (4:2) respectively.
Explanation of Solution
The reaction is represented as follows:
As per the balanced chemical equation,
1 mg HNO3 produces
10 mg HNO3 produces
1 mg HNO3 produces
10 mg HNO3 produces
Also,
1 mg HNO3 produces
10 mg HNO3 produces
Chapter 9 Solutions
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