Concept explainers
(a)
Interpretation:
The number of moles of the product produced by complete reaction of 1.00 g ammonia needs to be determined.
Concept Introduction:
If complete conversion of any reactant takes place in the
(a)
Explanation of Solution
The given reaction is as follows:
The molar mass of Ammonia (17.031 g/mol)
If there's 1.00 g of Ammonia to react, it can be converted into number of moles.
1 mole of ammonia give 1 mol of product (as per equation). Thus, the number of moles of product formed will be:
(b)
Interpretation:
The number of moles of the product produced by complete reaction of 1.00 g calcium oxide needs to be determined.
Concept Introduction:
If complete conversion of any reactant takes place in the chemical reaction, it is considered as a limiting reactant.
(b)
Explanation of Solution
The given reaction is as follows:
The molar mass of CaO is 56.077 g/mol.
If there's 1.00 g of Calcium Oxide to react, the number of moles can be calculated from molar mass of CaO and the number of moles of product formed will be:
(c)
Interpretation:
The number of moles of the product produced by complete reaction of 1.00 g sodium needs to be determined.
Concept Introduction:
If complete conversion of any reactant takes place in the chemical reaction, it is considered as a limiting reactant.
(c)
Explanation of Solution
The molar mass of Sodium (22.99 g/mol)
If there's 1.00 g of Sodium to react it can be converted into number of moles.
From the reaction ratio of Na to Na2O is 4:2 thus, number of moles of product formed will l be:
(d)
Interpretation:
The number of moles of the product produced by complete reaction of 1.00 g phosphorus needs to be determined.
Concept Introduction:
If complete conversion of any reactant takes place in the chemical reaction, it is considered as a limiting reactant.
(d)
Explanation of Solution
The given reaction is as follows:
The molar mass of Phosphorus (30.97 g/mol)
If there's 1.00 g of Phosphorus to react, it can be converted into number of moles.
The number of moles of product formed will be:
Chapter 9 Solutions
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