(a)
The determinant and the input impedance of the network when
(a)
Answer to Problem 7E
The determinant of the network is
Explanation of Solution
Given data:
The given diagram is shown in Figure 1.
Calculation:
The conversion of
The conversion of
The conversion of
The conversion of
The conversion of
The conversion of
For
The admittance of inductor is given by,
Substitute
For
The admittance of inductor is given by,
Substitute
For
The admittance of capacitor is given by,
Substitute
For
The admittance of inductor is given by,
Substitute
The required diagram is shown in Figure 2.
The inductor and the capacitor are in series.
The modified diagram is shown in Figure 3.
The expression for
The admittance
The modified diagram is shown in Figure 4.
The expression of
The admittance
The modified diagram is shown in Figure 5.
The expression of
Substitute
Further solve as,
The input admittance is the parallel combination of the inductor and
The expression of the input admittance
Substitute
Substitute
Mark the node voltages as
The required diagram is shown in Figure 6.
The equation at node voltage
The equation at node voltage
Substitute
Write equation (1) and (2) in matrix form.
The determinant of the given circuit is given by,
Further solve as,
Conclusion:
Therefore, the determinant of the network is,
(b)
The voltage across the current source.
(b)
Answer to Problem 7E
The voltage across the current source is
Explanation of Solution
Given data:
The value of the current source is,
The frequency is
Calculation:
The required diagram is shown in Figure 7.
The expression for the voltage across current source is given by,
Here,
Substitute
Conclusion:
Therefore, the voltage across the current source is
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Chapter 16 Solutions
Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
- b. Realize the following system function using minimum number of multipliers 1 1 1 H(z) + z-2 + +Z + 3 2 3arrow_forward*9. For the network of Fig. 16.47: a. Find the total admittance Y7. b. Find the voltages V, and V2. c. Find the current Iz. 30 R3 R - 6.8 1 3 R2 = 8.20 I = 3 AZ 30° Xcz R4 ellarrow_forward16.8 304200V 6 2 MW 4 a Practice: || Find the Thevenin equivalent at terminals a-b of the below circuit: b oy Answer: | 7y, = 124 - j32 9, Vi = 18.97/—51.57°V.arrow_forward
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