Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
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Question
Chapter 2, Problem 2.67P
Interpretation Introduction
Interpretation:
It is to be explained that for small rings, there is a significant difference in boiling points of cyclic
Concept introduction:
When compounds contain both polar and nonpolar groups, the strength of intermolecular attraction depends on the size of the nonpolar group. As the size of the nonpolar part increases, the contribution of induced dipole-induced dipole interactions toward the total strength becomes more significant than the contribution of the polar
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b. Consider the equilibrium shown below. When the solvent is ethanol (CH3CH₂OH), conformer B is
preferred. However, when the solvent is carbon tetrachloride (CCl4), conformer A is preferred. Use
drawings to illustrate the non-covalent interactions responsible for the different conformational
preference in these two different solvents. Minimal text may be used to further support your
explanation.
OH
A
OH
НО
B
OH
Arrange the following in DECREASING order of boiling point.
heptane
2,4-dimethylpentane
3-methylhexane
II
II
O a. I| > III >|
O b. III > || >|
O c. T> III >||
Ос.
|> I||
O d.
III> I > ||
Rank from highest to lowest boiling point. To rank items as equivalent, overlap them..
View Available Hint(s)
Highest BP
octane, Cali
butane, C₂H paraffin, CH 22,4-trimethylpentane, Cala
Cylly
hexadecane, CisH
Reset
Lowest BP
Chapter 2 Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
Ch. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10P
Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. 2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. 2.33PCh. 2 - Prob. 2.34PCh. 2 - Prob. 2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. 2.37PCh. 2 - Prob. 2.38PCh. 2 - Prob. 2.39PCh. 2 - Prob. 2.40PCh. 2 - Prob. 2.41PCh. 2 - Prob. 2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. 2.44PCh. 2 - Prob. 2.45PCh. 2 - Prob. 2.46PCh. 2 - Prob. 2.47PCh. 2 - Prob. 2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.1YTCh. 2 - Prob. 2.2YTCh. 2 - Prob. 2.3YTCh. 2 - Prob. 2.4YTCh. 2 - Prob. 2.5YTCh. 2 - Prob. 2.6YTCh. 2 - Prob. 2.7YTCh. 2 - Prob. 2.8YTCh. 2 - Prob. 2.9YTCh. 2 - Prob. 2.10YTCh. 2 - Prob. 2.11YTCh. 2 - Prob. 2.12YTCh. 2 - Prob. 2.13YTCh. 2 - Prob. 2.14YTCh. 2 - Prob. 2.15YTCh. 2 - Prob. 2.16YTCh. 2 - Prob. 2.17YTCh. 2 - Prob. 2.18YTCh. 2 - Prob. 2.19YTCh. 2 - Prob. 2.20YT
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- 1. Consider the solubility and boiling point of the following pair of compounds: n-butyl alcohol and diethyl ether. The boiling points for the compounds are 118 °C and 35 °C respectively. The solubility for both compounds is the same (8g/100g water). Explain this observation for (i) boiling point disparity; (ii) solubility similarity a. H-bonds form in diethyl ether; n-butyl alcohol forms H-bonds in water b. H-bonds form in n-butyl alcohol; diethyl ether forms H-bonds in water c. H-bonds in n-butyl alcohol; Both compounds form H-bonds in water d. Both compounds form H-bonds; Both compounds form H-bonds in water 2. Account for the bond angle differences between (i) H-C-H (109.5°) in methane and H-S-H (90°); H-C-H (109.5°) and H-O-H (107.5°) in water. a. The H-S-H has two lone pairs; The H-O-H has two lone pairs b. The H-S-H has no hybridization at p-orbitals; The H-O-H has two lone pairs c. The H-S-H has two lone pairs; The H-O-H has no hybridization…arrow_forwardTwo isomers of C2H2F2 are shown. Circle the one that you would you expect to have the highest boiling point and explain your reasoning. H. H. H. F isomer A isomer Barrow_forwardExplain the observed trend in the melting points for four isomers of molecular formula C,H16. mp (°C) CH;CH,CH,CH(CH)CH,CH3 CH,CH,CH2CH,CH(CHa)2 CH3CH2CH2CH,CH;CH¿CH3 (CHa,CHC(CH3)3 -119 -118 -91 -25arrow_forward
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