Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 2.SE, Problem 61AP
Phenol, C6H5OH, is a stronger acid than methanol, CH3OH, even though both contain an Q-H bond. Draw the structures of the anions resulting from loss of H+ from phenol and methanol, and use resonance structures to explain the difference in acidity.
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Phenol, C6H5OH, methanol, and CH3OH both have O-H groups, but phenol is a stronger acid. Draw the structure of the anion produced by removing H+ from each compound and explain the difference in acidity using the resonance structure.
Calculate the Enthalpy Change (ΔH) from average bond energies, which have been listed below in KJ/mol, for the following reaction and identify the nature of the reaction:
CH3COOH + CH3OH → CH3COOCH3 + H2O
[C‒H: 413; C‒C: 347; C=O: 745; C=C: 614; Cl‒Cl: 239, C‒O: 358; O‒H: 467]
I need this solution, Calculate the Enthalpy Change (ΔH) from average bond energies, which have been listed below in KJ/mol, for the following reaction and identify the nature of the reaction:
CH3COOH + CH3OH → CH3COOCH3 + H2O
[C‒H: 413; C‒C: 347; C=O: 745; C=C: 614; Cl‒Cl: 239, C‒O: 358; O‒H: 467
Chapter 2 Solutions
Organic Chemistry
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