Concept explainers
(a)
Interpretation:
Given Lewis structure is to be drawn using condensed formula.
Concept introduction:
The condensed formula indicates how the atoms should be connected in a given molecule. To arrive at a total charge of zero, each carbon should have a maximum of four bonds while each oxygen should have a maximum of two bonds and two lone pairs. A parenthesis in the condensed formula represents that the repetitive unit is attached to the previous carbon atom. The
Answer to Problem 1.61P
The condensed formula for the first Lewis structure is:
Explanation of Solution
The given Lewis structure is:
In the given Lewis structure, there are two
The condensed formula for the first Lewis structure is shown as:
(b)
Interpretation:
Given Lewis structure is to be drawn using condensed formula.
Concept introduction:
The condensed formula indicates how the atoms should be connected in a given molecule. To arrive at a total charge of zero, each carbon should have a maximum of four bonds while each oxygen should have a maximum of two bonds and two lone pairs. A parenthesis in the condensed formula represents that the repetitive unit is attached to the previous carbon atom. The
Answer to Problem 1.61P
The condensed structure for the given Lewis structure is:
Explanation of Solution
The given Lewis structure is:
In the structure above, there are two
The condensed formula for the given Lewis structure is shown as:
(c)
Interpretation:
Given Lewis structure is to be drawn using condensed formula.
Concept introduction:
The condensed formula indicates how the atoms should be connected in a given molecule. To arrive at a total charge of zero, each carbon should have a maximum of four bonds while each oxygen should have a maximum of two bonds and two lone pairs. A parenthesis in the condensed formula represents that the repetitive unit is attached to the previous carbon atom. The
Answer to Problem 1.61P
The condensed structure for the given Lewis structure is:
Explanation of Solution
The given Lewis structure is:
In the structure above, there are two
The condensed formula for the given Lewis structure is shown as:
(d)
Interpretation:
Given Lewis structure is to be drawn using condensed formula.
Concept introduction:
The condensed formula indicates how the atoms should be connected in a given molecule. To arrive at a total charge of zero, each carbon should have a maximum of four bonds while each oxygen should have a maximum of two bonds and two lone pairs. A parenthesis in the condensed formula represents that the repetitive unit is attached to the previous carbon atom. The
Answer to Problem 1.61P
The condensed structure for the given Lewis structure is:
Explanation of Solution
The given Lewis structure is:
The structure above is a five carbon ring structure. Rings are generally now shown in their condensed formulas, but they are commonly shown in their partially condensed form. Thus, the condensed formula for the given Lewis structure is:
The condensed formula for the given Lewis structure is shown in Figure 1.
(e)
Interpretation:
Given Lewis structure is to be drawn using condensed formula.
Concept introduction:
The condensed formula indicates how the atoms should be connected in a given molecule. To arrive at a total charge of zero, each carbon should have a maximum of four bonds while each oxygen should have a maximum of two bonds and two lone pairs. A parenthesis in the condensed formula represents that the repetitive unit is attached to the previous carbon atom. The
Answer to Problem 1.61P
The condensed structure for the given Lewis structure is:
Explanation of Solution
The given Lewis structure is:
In the structure above, there is a five membered ring on the left side and a branch of three carbon atoms. Rings are generally now shown in their condensed formulas, but they are commonly shown in their partially condensed form. On one of the carbon atoms in the five membered ring, two
Thus, the condensed formula for the given Lewis structure is:
The condensed formula for the given Lewis structure is shown in Figure 2.
(f)
Interpretation:
Given Lewis structure is to be drawn using condensed formula.
Concept introduction:
The condensed formula indicates how the atoms should be connected in a given molecule. To arrive at a total charge of zero, each carbon should have a maximum of four bonds while each oxygen should have a maximum of two bonds and two lone pairs. A parenthesis in the condensed formula represents that the repetitive unit is attached to the previous carbon atom. The
Answer to Problem 1.61P
The condensed structure for the given Lewis structure is:
Explanation of Solution
The given Lewis structure is:
In the structure above, a
The condensed formula for the given Lewis structure is
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Chapter 1 Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
- Draw complete Lewis structures for the following condensed structural formulas.(a) CH3(CH2)3CH(CH3)2 (b) (CH3)2CHCH2Cl(c) CH3CH2COCN (d) CH2CHCHO(e) (CH3)3CCOCHCH2 (f) CH3COCOOHarrow_forwardDraw Lewis structures for the following molecules. Include all lone pairs and H atoms. (a) OH (b) CI CI (c) (d) (e) (f) (g) (h) (i) H3Narrow_forwardDraw Lewis structures for each of the following compounds. In each case, specify the number of valence electrons surrounding the central atom. (Assign lone pairs and radical electrons where appropriate.) (Assume the central atom does not contain an expanded octet.) (a) bromine dioxide (BrO2) (b) beryllium bromide (BeBr2) (c) phosphorus pentafluoride (PF5)arrow_forward
- Judging from their relative positions in the Periodic Table, which atom in each set is more electronegative? (a) Carbon or nitrogen (b) Chlorine or bromine (c) Oxygen or sulfurarrow_forwardAll of the hydrogens are bonded to carbon in both of the following. Write a Lewis formula that satisfies the octet rule for each.(a) Formaldehyde (CH2O) (b) Hydrogen cyanide (HCN)arrow_forwardDraw a Lewis Structure for each of the following species and assign formal charge where appropriate. Using electronegative values from the period table that was provided identify polar covalent bonds and label the atoms δ+ and δ−. For each of the molecules indicate whether or not it has a dipole moment. (a)CH5N (b) HCN (c) H2CO (d) CH3NC(e) CH3SOCH3 (f) H6BNarrow_forward
- Which compound contains the most polar bond? (A) (B) F (C) (D) Compound D Compound C O Compound A Compound B uestion oCarrow_forwardDraw Lewis structures for the following molecules and ion. (c) H2O2 (a) NCl3 (b) OCS (d) HCOO−arrow_forwardIn which of the following ions does carbon have a formal charge? Explain your answer. A) I B) II C) III D) None of thesearrow_forward
- Compute the formal charge (FC) on each atom in the following structures.(a) Methane (CH4)arrow_forwardIdentify the electron geometry about each charged atom. Where appropriate, indicate the molecular geometry and approximate bond angle as well. (a) (b) (c) (d) CH3 (e) (f) O `NH H3CN-CH3 CH3arrow_forwardDraw Lewis structures for the following compounds and ions, showing appropriateformal charges.(a) [CH3OH2 ]+ (b) NH4Cl (c) (CH3)4NCl(d) NaOCH3 (e) +CH3 (f) -CH3(g) NaBH4 (h) NaBH3CN (i) (CH3)2O¬BF3(j) [HONH3]+ (k) KOC(CH3)3 (l) [H2C“OH]arrow_forward
- Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning