The leaving group in the given molecule is to be determined inorder identify the positively charged and negatively charged fragments produced during mechanism. Concept Introduction: Heterolytic cleavage of sigma bond occurs under a variety of conditions. The mechanism of bond cleavage is as shown below, The arrow in the above mechanism indicates that the sigma electrons form A-B bond are leaving A and becoming the exclusive property of B. Since the fragment A is formally losing one electron, it must become positively charged and B must become negatively charged since it gains an electron.

Question

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Answer 1

Question

Chapter 3, Problem 1EQ

Interpretation Introduction

Interpretation:

The leaving group in the given molecule is to be determined inorder identify the positively charged and negatively charged fragments produced during mechanism.

Concept Introduction:

Heterolytic cleavage of sigma bond occurs under a variety of conditions. The mechanism of bond cleavage is as shown below,

The arrow in the above mechanism indicates that the sigma electrons form A-B bond are leaving A and becoming the exclusive property of B. Since the fragment A is formally losing one electron, it must become positively charged and B must become negatively charged since it gains an electron.

Expert Solution & Answer

Answer to Problem 1EQ

The mechanism yields a negatively charged Chloride ion and positively charged isopropyl cation.

Explanation of Solution

The given Lewis structure of isopropyl chloride:

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 2

Chlorine is the leaving group in this case. As Chlorine is more electronegative, it obtains the shared electron pair during heterolytic bond cleavage as shown below.

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 3

Hence, the cleavage of isopropyl chloride yields chloride ion (negatively charged as shared electron is obtained) and isopropyl cation.

Conclusion

The positive and negative fragments produced in the mechanism are identified.

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Answer 2

Question

Chapter 3, Problem 1EQ

Interpretation Introduction

Interpretation:

The leaving group in the given molecule is to be determined inorder identify the positively charged and negatively charged fragments produced during mechanism.

Concept Introduction:

Heterolytic cleavage of sigma bond occurs under a variety of conditions. The mechanism of bond cleavage is as shown below,

The arrow in the above mechanism indicates that the sigma electrons form A-B bond are leaving A and becoming the exclusive property of B. Since the fragment A is formally losing one electron, it must become positively charged and B must become negatively charged since it gains an electron.

Expert Solution & Answer

Answer to Problem 1EQ

The mechanism yields a negatively charged Chloride ion and positively charged isopropyl cation.

Explanation of Solution

The given Lewis structure of isopropyl chloride:

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 2

Chlorine is the leaving group in this case. As Chlorine is more electronegative, it obtains the shared electron pair during heterolytic bond cleavage as shown below.

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 3

Hence, the cleavage of isopropyl chloride yields chloride ion (negatively charged as shared electron is obtained) and isopropyl cation.

Conclusion

The positive and negative fragments produced in the mechanism are identified.

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Answer 3

Question

Chapter 3, Problem 1EQ

Interpretation Introduction

Interpretation:

The leaving group in the given molecule is to be determined inorder identify the positively charged and negatively charged fragments produced during mechanism.

Concept Introduction:

Heterolytic cleavage of sigma bond occurs under a variety of conditions. The mechanism of bond cleavage is as shown below,

The arrow in the above mechanism indicates that the sigma electrons form A-B bond are leaving A and becoming the exclusive property of B. Since the fragment A is formally losing one electron, it must become positively charged and B must become negatively charged since it gains an electron.

Expert Solution & Answer

Answer to Problem 1EQ

The mechanism yields a negatively charged Chloride ion and positively charged isopropyl cation.

Explanation of Solution

The given Lewis structure of isopropyl chloride:

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 2

Chlorine is the leaving group in this case. As Chlorine is more electronegative, it obtains the shared electron pair during heterolytic bond cleavage as shown below.

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 3

Hence, the cleavage of isopropyl chloride yields chloride ion (negatively charged as shared electron is obtained) and isopropyl cation.

Conclusion

The positive and negative fragments produced in the mechanism are identified.

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Answer 4

Question

Chapter 3, Problem 1EQ

Interpretation Introduction

Interpretation:

The leaving group in the given molecule is to be determined inorder identify the positively charged and negatively charged fragments produced during mechanism.

Concept Introduction:

Heterolytic cleavage of sigma bond occurs under a variety of conditions. The mechanism of bond cleavage is as shown below,

The arrow in the above mechanism indicates that the sigma electrons form A-B bond are leaving A and becoming the exclusive property of B. Since the fragment A is formally losing one electron, it must become positively charged and B must become negatively charged since it gains an electron.

Expert Solution & Answer

Answer to Problem 1EQ

The mechanism yields a negatively charged Chloride ion and positively charged isopropyl cation.

Explanation of Solution

The given Lewis structure of isopropyl chloride:

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 2

Chlorine is the leaving group in this case. As Chlorine is more electronegative, it obtains the shared electron pair during heterolytic bond cleavage as shown below.

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 3

Hence, the cleavage of isopropyl chloride yields chloride ion (negatively charged as shared electron is obtained) and isopropyl cation.

Conclusion

The positive and negative fragments produced in the mechanism are identified.

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Answer 5

Chapter 3, Problem 1EQ

Interpretation Introduction

Interpretation:

The leaving group in the given molecule is to be determined inorder identify the positively charged and negatively charged fragments produced during mechanism.

Concept Introduction:

Heterolytic cleavage of sigma bond occurs under a variety of conditions. The mechanism of bond cleavage is as shown below,

The arrow in the above mechanism indicates that the sigma electrons form A-B bond are leaving A and becoming the exclusive property of B. Since the fragment A is formally losing one electron, it must become positively charged and B must become negatively charged since it gains an electron.

Expert Solution & Answer

Answer to Problem 1EQ

The mechanism yields a negatively charged Chloride ion and positively charged isopropyl cation.

Explanation of Solution

The given Lewis structure of isopropyl chloride:

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 2

Chlorine is the leaving group in this case. As Chlorine is more electronegative, it obtains the shared electron pair during heterolytic bond cleavage as shown below.

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 3

Hence, the cleavage of isopropyl chloride yields chloride ion (negatively charged as shared electron is obtained) and isopropyl cation.

Conclusion

The positive and negative fragments produced in the mechanism are identified.

Answer 6

Chapter 3, Problem 1EQ

Interpretation Introduction

Interpretation:

The leaving group in the given molecule is to be determined inorder identify the positively charged and negatively charged fragments produced during mechanism.

Concept Introduction:

Heterolytic cleavage of sigma bond occurs under a variety of conditions. The mechanism of bond cleavage is as shown below,

The arrow in the above mechanism indicates that the sigma electrons form A-B bond are leaving A and becoming the exclusive property of B. Since the fragment A is formally losing one electron, it must become positively charged and B must become negatively charged since it gains an electron.

Expert Solution & Answer

Answer to Problem 1EQ

The mechanism yields a negatively charged Chloride ion and positively charged isopropyl cation.

Explanation of Solution

The given Lewis structure of isopropyl chloride:

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 2

Chlorine is the leaving group in this case. As Chlorine is more electronegative, it obtains the shared electron pair during heterolytic bond cleavage as shown below.

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 3

Hence, the cleavage of isopropyl chloride yields chloride ion (negatively charged as shared electron is obtained) and isopropyl cation.

Conclusion

The positive and negative fragments produced in the mechanism are identified.

Answer 7

Chapter 3, Problem 1EQ

Interpretation Introduction

Interpretation:

The leaving group in the given molecule is to be determined inorder identify the positively charged and negatively charged fragments produced during mechanism.

Concept Introduction:

Heterolytic cleavage of sigma bond occurs under a variety of conditions. The mechanism of bond cleavage is as shown below,

The arrow in the above mechanism indicates that the sigma electrons form A-B bond are leaving A and becoming the exclusive property of B. Since the fragment A is formally losing one electron, it must become positively charged and B must become negatively charged since it gains an electron.

Answer 8

Expert Solution & Answer

Answer to Problem 1EQ

The mechanism yields a negatively charged Chloride ion and positively charged isopropyl cation.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

The given Lewis structure of isopropyl chloride:

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 2

Chlorine is the leaving group in this case. As Chlorine is more electronegative, it obtains the shared electron pair during heterolytic bond cleavage as shown below.

Pushing Electrons, Chapter 3, Problem 1EQ , additional homework tip 3

Hence, the cleavage of isopropyl chloride yields chloride ion (negatively charged as shared electron is obtained) and isopropyl cation.

Answer 12

Conclusion

The positive and negative fragments produced in the mechanism are identified.

Answer 13

Ch. 3 - Prob. 1EQ Ch. 3 - Prob. 2EQ Ch. 3 - Prob. 3EQ Ch. 3 - Prob. 4EQ Ch. 3 - Prob. 5EQ Ch. 3 - Prob. 6EQ Ch. 3 - Here are some exercises in sigma bond breaking....Ch. 3 - Prob. 8EQ Ch. 3 - Prob. 9EQ Ch. 3 - Prob. 10EQ

Concept explainers

Answer to Problem 1EQ

Explanation of Solution

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Chapter 3 Solutions