Organic Chemistry
Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 5, Problem 5.30AP
Interpretation Introduction

(a)

Interpretation:

Whether the peroxide is present or not, the structure of a five-carbon alkene that would give same product from reaction with hydrogen bromide is to be drawn.

Concept introduction:

The addition of one or more than one halogen atom in an aromatic compound is known as halogenation reaction. The pathway of the halogenation reaction depends on the structure of the substrate. These reactions proceed via free-radical chain reaction.

Interpretation Introduction

(b)

Interpretation:

The structure of a compound with formula C6H12 that would not undergo ozonolysis is to be drawn.

Concept introduction:

In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide.

Interpretation Introduction

(c)

Interpretation:

The structure of four compounds with formula C7H12 that would undergo catalytic hydrogenation to give methylcyclohexane is to be stated.

Concept introduction:

The addition of H2 in presence of catalyst is known as catalytic hydrogenation reaction. This is a syn addition. Alkene is reduced to alkane. In this reaction weak pi bond of alkene and sigma bond between H2 is broken and two CH bonds are formed.

Interpretation Introduction

(d)

Interpretation:

The structure of two alkenes that would give only one product after oxymercuration-reduction followed by alkaline NaBH4 is to be stated.

Concept introduction:

The oxymercuration reaction is an electrophilic addition reaction that converts an alkene into an alcohol and an alkyne into a ketone. The reagents required for this reaction are [1]Hg(OAc)2;[2]H2O,Et2OorTHF.

Interpretation Introduction

(e)

Interpretation:

The structure of an alkene that would give 2-pentanone as the only product after ozonolysis followed by treatment with aqueous H2O2 is to be stated.

Concept introduction:

In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide.

Interpretation Introduction

(f)

Interpretation:

The structure of alkene that would give the alcohol after hydroboration-oxidation is to be drawn.

Concept introduction:

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.

Anti markovinkov rule states that the positive part of acid attached to that carbon atom in C=C bond which carries minimum number of hydrogen atoms and the negative part of acid will attach to that carbon atom in C=C bond which has maximum number of hydrogen atoms.

Interpretation Introduction

(g)

Interpretation:

The structure of an alkene with the formula C6H12 that would give same product as a result of either oxymercuration-reduction or hydroboration-oxidation is to be drawn.

Concept introduction:

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.

Anti markovinkov rule states that the positive part of acid attached to that carbon atom in C=C bond which carries minimum number of hydrogen atoms and the negative part of acid will attach to that carbon atom in C=C bond which has maximum number of hydrogen atoms.

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Students have asked these similar questions
(a) Draw the structure of a compound of molecular formula C6H10 that reacts with H2 in the presence of Pd-C but does not react with H2 in the presence of Lindlar catalyst. (b) Draw the structure of a compound of molecular formula C6H10 that reacts with H2 when either catalyst is present.
(a) rate at which the following alcohols undergo dehydration to form alkenes in sulfuric acid OH OH OH (b) rate at which the following alkenes undergo addition with HBr to form an alkyl halide
(b) Consider the reaction of 1-bromobutane with a large excess of ammonia (NH3). Draw the reactants, the transition state, andthe products. Note that the initial product is the salt of an amine (RNH3+ Br - ), which is deprotonated by the excess ammonia to give the amine.
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